Surface Areas and Volumes
Surface Areas and Volumes
Surface areas and volumes of solids made by combining cuboids, cylinders, cones, spheres and hemispheres, weighted towards the cone-and-hemisphere toy and cone-volume questions set across the 2026 papers.
18 cards
- Why is the total surface area of a combined solid usually not the sum of the total surface areas of its parts?
- When two solids are joined, the faces pressed together are hidden and no longer part of the outside surface. Only the exposed surfaces count, so a top made of a cone on a hemisphere has area CSA of hemisphere + CSA of cone.
- Why is the volume of a combined solid simply the sum of the volumes of its parts?
- Joining solids hides some surface, but no space inside either solid is lost. So, unlike surface area, the volume of the new solid is the total of the constituent volumes.
- Curved surface area of a hemisphere
- 2πr², which is half of the sphere's surface area 4πr². If the flat circular face is exposed too, add its area πr².
- Slant height of a cone
- l = √(r² + h²), where r is the base radius and h the vertical height. The radius, height and slant height form a right triangle.
- Curved surface area of a cone
- πrl, where r is the base radius and l the slant height.
- Curved surface area of a cylinder
- 2πrh, where r is the base radius and h the height. Add πr² for each circular end that is part of the surface.
- Surface area of a cube
- 6 × (edge)², since a cube has six equal square faces.
- Volume of a cylinder
- πr²h, where r is the base radius and h the height. Half a cylinder has volume ½πr²h.
- Volume of a cone
- ⅓πr²h, one-third of the volume of a cylinder with the same base radius and height.
- Volume of a hemisphere
- ⅔πr³, half the volume of a sphere of the same radius.
- A top is a cone on a hemisphere, 5 cm tall overall with diameter 3.5 cm. How do you find the area to colour?
- The area is CSA of hemisphere + CSA of cone. The hemisphere's radius 1.75 cm is part of the height, so the cone is 5 − 1.75 = 3.25 cm tall and its slant height is about 3.7 cm. Then 2πr² + πrl ≈ 39.6 cm².
- A hemisphere of diameter 4.2 cm sits on a cube of edge 5 cm. How do you find the block's total surface area?
- Start with the cube's 150 cm², remove the circle covered by the hemisphere (πr²) and add the hemisphere's curved surface (2πr²). The net change is +πr², giving 150 + 13.86 = 163.86 cm².
- A rocket is a cone of base radius 2.5 cm on a narrower cylinder of radius 1.5 cm. How do you work out the cone's painted area?
- Paint the cone's curved surface plus the ring of its base left uncovered by the cylinder: πrl + πr² − πr′². With slant height 6.5 cm this is 3.14 × 20.25 ≈ 63.585 cm².
- A bird-bath is a cylinder of height 1.45 m and radius 30 cm with a hemispherical hollow at the top. How do you find its total surface area?
- Only the cylinder's curved surface and the inside of the hemispherical hollow are counted: 2πrh + 2πr² = 2πr(h + r). With r = 30 cm and h = 145 cm this is 33000 cm², or 3.3 m².
- A shed is a 15 m × 7 m × 8 m cuboid topped by a half cylinder. How do you find the air it holds with machinery and workers inside?
- Add the cuboid's volume to half the cylinder's (diameter 7 m, length 15 m) to get 1128.75 m³. Then subtract the space taken by the machinery (300 m³) and the workers (1.6 m³), leaving 827.15 m³.
- A cylindrical glass has a raised hemispherical bottom. How do you find its actual capacity?
- Its apparent capacity is the cylinder's volume, πr²h, here 196.25 cm³. The raised hemisphere takes up ⅔πr³, about 32.71 cm³, so the actual capacity is the difference, 163.54 cm³.
- A toy is a cone of height 2 cm on a hemisphere of radius 2 cm. How do you find the space between it and a cylinder that just encloses it?
- Toy volume = ⅔πr³ + ⅓πr²h = 25.12 cm³. The enclosing cylinder has radius 2 cm and height 2 + 2 = 4 cm, so its volume is 3.14 × 4 × 4 = 50.24 cm³. The difference is 25.12 cm³.
- Two equal cubes of edge a are joined face to face into a cuboid. Why is its surface area 10a² rather than 12a²?
- Each cube has 6 faces of area a², 12 in all, but the two faces pressed together are hidden inside the cuboid. That leaves 10 exposed faces, so the surface area is 10a².
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